Practice
Percents and Equations Practice
Fifty original questions covering part, rate, whole, translations, proportions, unusual rates, reverse equations, and error analysis.
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Question 1
Explanation
Use \(P=rW\): \(P=0.18(250)=45\).
Question 2
Explanation
Use \(P=rW\): \(P=0.32(175)=56\).
Question 3
Explanation
Use \(P=rW\): \(P=0.075(640)=48\).
Question 4
Explanation
Use \(P=rW\): \(P=1.25(84)=105\).
Question 5
Explanation
Use \(P=rW\): \(P=0.006(3500)=21\).
Question 6
Explanation
Solve \(42=r(168)\): \(r=42/168=0.25\), which is \(25\%\).
Question 7
Explanation
Solve \(54=r(120)\): \(r=54/120=0.45\), which is \(45\%\).
Question 8
Explanation
Solve \(18=r(480)\): \(r=18/480=0.0375\), which is \(3.75\%\).
Question 9
Explanation
Solve \(156=r(120)\): \(r=156/120=1.3\), which is \(130\%\).
Question 10
Explanation
Solve \(7=r(2800)\): \(r=7/2800=0.0025\), which is \(0.25\%\).
Question 11
Explanation
Let the whole be \(W\). Then \(63=0.35W\), so \(W=63/0.35=180\).
Question 12
Explanation
Let the whole be \(W\). Then \(144=0.6W\), so \(W=144/0.6=240\).
Question 13
Explanation
Let the whole be \(W\). Then \(27=0.075W\), so \(W=27/0.075=360\).
Question 14
Explanation
Let the whole be \(W\). Then \(96=1.2W\), so \(W=96/1.2=80\).
Question 15
Explanation
Let the whole be \(W\). Then \(4.5=0.005W\), so \(W=4.5/0.005=900\).
Question 16
Explanation
The rate in decimal form is \(0.004\). Therefore \(P=0.004(320)=1.28\).
Question 17
Explanation
The rate in decimal form is \(2.5\). Therefore \(P=2.5(72)=180\).
Question 18
Explanation
The rate in decimal form is \(0.00075\). Therefore \(P=0.00075(8400)=6.3\).
Question 19
Explanation
The rate in decimal form is \(1.625\). Therefore \(P=1.625(48)=78\).
Question 20
Explanation
The rate in decimal form is \(0.012\). Therefore \(P=0.012(1250)=15\).
Question 21
Explanation
In the master equation \(P=rW\), ‘is’ identifies the part and ‘of’ identifies the whole.
Question 22
Explanation
In the master equation \(P=rW\), ‘is’ identifies the part and ‘of’ identifies the whole.
Question 23
Explanation
In the master equation \(P=rW\), ‘is’ identifies the part and ‘of’ identifies the whole.
Question 24
Explanation
In the master equation \(P=rW\), ‘is’ identifies the part and ‘of’ identifies the whole.
Question 25
Explanation
In the master equation \(P=rW\), ‘is’ identifies the part and ‘of’ identifies the whole.
Question 26
Explanation
Use \(r=P/W\): \(r=48/160=0.3=30\%\).
Question 27
Explanation
Use \(r=P/W\): \(r=72/240=0.3=30\%\).
Question 28
Explanation
Use \(r=P/W\): \(r=81/360=0.225=22.5\%\).
Question 29
Explanation
Use \(r=P/W\): \(r=126/90=1.4=140\%\).
Question 30
Explanation
Use \(r=P/W\): \(r=15/1200=0.0125=1.25\%\).
Question 31
Explanation
Solve \(96=0.64W\). Dividing gives \(W=96/0.64=150\).
Question 32
Explanation
Solve \(378=0.84W\). Dividing gives \(W=378/0.84=450\).
Question 33
Explanation
Solve \(1560=0.65W\). Dividing gives \(W=1560/0.65=2400\).
Question 34
Explanation
Solve \(13.5=0.45W\). Dividing gives \(W=13.5/0.45=30\).
Question 35
Explanation
Solve \(91=1.3W\). Dividing gives \(W=91/1.3=70\).
Question 36
Explanation
Set \(18/45=p/100\). Cross-multiplication gives \(p=100(18)/45=40\).
Question 37
Explanation
Set \(63/84=p/100\). Cross-multiplication gives \(p=100(63)/84=75\).
Question 38
Explanation
Set \(22/160=p/100\). Cross-multiplication gives \(p=100(22)/160=13.75\).
Question 39
Explanation
Set \(132/88=p/100\). Cross-multiplication gives \(p=100(132)/88=150\).
Question 40
Explanation
Set \(3.6/480=p/100\). Cross-multiplication gives \(p=100(3.6)/480=0.75\).
Question 41
Explanation
The rate must be written as \(0.35\), so the part is \(28\).
Question 42
Explanation
The part must be divided by the whole: \(24/60=40\%\).
Question 43
Explanation
The unknown is the whole, so divide: \(54/0.30=180\).
Question 44
Explanation
Divide by \(100\): \(0.8\%=0.008\).
Question 45
Explanation
A rate above \(100\%\) produces a part greater than the whole.
Question 46
Explanation
Use \(P=rW\) and isolate the requested variable while keeping decimal and percent forms distinct.
Question 47
Explanation
Use \(P=rW\) and isolate the requested variable while keeping decimal and percent forms distinct.
Question 48
Explanation
Use \(P=rW\) and isolate the requested variable while keeping decimal and percent forms distinct.
Question 49
Explanation
Use \(P=rW\) and isolate the requested variable while keeping decimal and percent forms distinct.
Question 50
Explanation
Use \(P=rW\) and isolate the requested variable while keeping decimal and percent forms distinct.
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Questions to review
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- Question 1Finding the partEasy
- Question 2Finding the partEasy
- Question 3Finding the partEasy
- Question 4Finding the partEasy
- Question 5Finding the partEasy
- Question 6Finding the percent rateEasy
- Question 7Finding the percent rateEasy
- Question 8Finding the percent rateEasy
- Question 9Finding the percent rateEasy
- Question 10Finding the percent rateEasy
- Question 11Finding the wholeEasy
- Question 12Finding the wholeEasy
- Question 13Finding the wholeEasy
- Question 14Finding the wholeEasy
- Question 15Finding the wholeEasy
- Question 16Unusual percent ratesMedium
- Question 17Unusual percent ratesMedium
- Question 18Unusual percent ratesMedium
- Question 19Unusual percent ratesMedium
- Question 20Unusual percent ratesMedium
- Question 21Translating percent languageMedium
- Question 22Translating percent languageMedium
- Question 23Translating percent languageMedium
- Question 24Translating percent languageMedium
- Question 25Translating percent languageMedium
- Question 26Part-rate-whole tablesMedium
- Question 27Part-rate-whole tablesMedium
- Question 28Part-rate-whole tablesMedium
- Question 29Part-rate-whole tablesMedium
- Question 30Part-rate-whole tablesMedium
- Question 31Reverse percent equationsMedium
- Question 32Reverse percent equationsMedium
- Question 33Reverse percent equationsMedium
- Question 34Reverse percent equationsMedium
- Question 35Reverse percent equationsMedium
- Question 36Percent proportionsMedium
- Question 37Percent proportionsMedium
- Question 38Percent proportionsMedium
- Question 39Percent proportionsMedium
- Question 40Percent proportionsMedium
- Question 41Percent-equation error analysisHard
- Question 42Percent-equation error analysisHard
- Question 43Percent-equation error analysisHard
- Question 44Percent-equation error analysisHard
- Question 45Percent-equation error analysisHard
- Question 46Symbolic percent equationsHard
- Question 47Symbolic percent equationsHard
- Question 48Symbolic percent equationsHard
- Question 49Symbolic percent equationsHard
- Question 50Symbolic percent equationsHard