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MathChapter 11: Quadratic Functions
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About 24 minutes
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Completing the square rewrites a quadratic so the variable appears inside one squared binomial. The method is systematic and works even when integer factoring is inconvenient.

Square-root principle

The term that completes a square

Perfect-square completion
\[x^2+bx+\left(\frac b2\right)^2=\left(x+\frac b2\right)^2\]

Take half of the linear coefficient and square that result. Do not confuse \(\left(\frac b2\right)^2\) with \(\frac{b^2}{2}\).

  1. Move the constant

    Separate the variable terms from the constant.

  2. Normalize

    If the leading coefficient is not \(1\), divide every term by it.

  3. Half and square

    Calculate \(\left(\frac b2\right)^2\) using the normalized linear coefficient.

  4. Balance

    Add that same value to both sides.

  5. Factor

    Rewrite the left side as a perfect-square binomial.

  6. Square root

    Take both square roots and isolate the variable.

Complete the square without changing the equation

A seven-step equation flow that normalizes the leading coefficient, adds the same square to both sides, and retains both square-root branches.

  1. Original\[2x^2-12x+5=0\]

    Write the equation in standard form.

  2. Move the constant\[2x^2-12x=-5\]

    Subtract the constant from both sides.

  3. Normalize\[x^2-6x=-\frac{5}{2}\]

    Divide every term by the leading coefficient.

  4. Add the square\[x^2-6x+9=-\frac{5}{2}+9\]

    Half of negative six is negative three; its square is nine.

  5. Perfect-square form\[(x-3)^2=\frac{13}{2}\]

    Factor the left and simplify the right.

  6. Take both square roots\[x-3=\pm\frac{\sqrt{26}}{2}\]

    The plus-or-minus sign preserves both solutions.

  7. Solutions\[x=3\pm\frac{\sqrt{26}}{2}\]

    Both values satisfy the original equation.

Worked example

Complete the square with an odd linear coefficient

Solve \(x^2+5x-1=0\).

  1. Move

    \(x^2+5x=1\).

  2. Complete

    Add \(\left(\frac52\right)^2=\frac{25}{4}\) to both sides.

  3. Factor

    \(\left(x+\frac52\right)^2=\frac{29}{4}\).

  4. Square root

    \(x+\frac52=\pm\frac{\sqrt{29}}{2}\).

\(x=\frac{-5\pm\sqrt{29}}{2}\).

Definition of equal polynomials

Worked example

Compare coefficients in an identity

If \(3x^2+(k-2)x+7=3x^2+5x+7\) for every \(x\), find \(k\).

  1. Match linear coefficients

    \(k-2=5\).

  2. Solve

    \(k=7\).

\(k=7\).

Common mistakes

  • Add \(\left(\frac b2\right)^2\), not \(\frac{b^2}{2}\) or \(\frac b2\).
  • Add the completion term to both sides to preserve equality.
  • Divide every term by \(a\) before completing the square when \(a\ne1\).
  • Keep the \(\pm\) branch after taking square roots.
  • Compare coefficients only when two polynomials are equal for every input.
Mini check

Find the completion term

What term completes \(x^2-14x\) to a perfect square?

  1. \(-7\)
  2. \(7\)
  3. \(49\)
  4. \(196\)
Show answer and explanation

Answer: \(49\)

Half of \(-14\) is \(-7\), and \((-7)^2=49\).

Key takeaways

Key takeaways

What to remember

  • Normalize the squared-term coefficient before completing the square.
  • Add \(\left(\frac b2\right)^2\) to both sides.
  • The perfect-square binomial uses the sign of half the linear coefficient.
  • Taking a square root while solving requires both \(\pm\) branches.
Continue learning

Put these notes into practice

Apply the ideas with SAT-style questions, then reinforce key details with flashcards.