SAT / Math / Problem-Solving & Data Analysis / Probability / Notes Math Problem-Solving & Data Analysis
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About 26 minutes On this page Essential concepts SAT strategy and application Mistakes and traps Key takeaways Probability measures how likely an event is on a scale from 0 to 1. SAT questions may use equally likely outcomes, two-way tables, repeated selections, or conditional language such as ‘given that.’
Essential concepts Bookmark Key concept The denominator is the relevant sample space For an unconditional probability, count all possible outcomes. For a conditional probability, restrict the denominator to outcomes satisfying the stated condition.
Rule Decide whether events are combined with and or or For independent events joined by ‘and,’ multiply probabilities. For mutually exclusive alternatives joined by ‘or,’ add probabilities. Overlapping events require subtracting the overlap once.
Core probability relationships \[P(A)=rac{ ext{favorable outcomes}}{ ext{total outcomes}} qquad P(A^c)=1-P(A)\]
The complement rule is often faster when ‘at least one’ is easier to handle as one minus ‘none.’
SAT strategy and application → SAT strategy and application Bookmark SAT strategy Use a table or tree to define the sample space Organize categories before calculating. For selections without replacement, update both the favorable count and the total after the first selection.
Count favorable outcomes There are 3 red tokens.
Count total outcomes \(3+5=8\) tokens.
Probability: \(rac{3}{8}\) .
← Essential concepts Mistakes and traps → Mistakes and traps Bookmark Common mistake Using the wrong conditional denominator If the question says ‘among students who play an instrument,’ the denominator includes only instrument players, not all students.
Common trap Treating dependent selections as independent Without replacement, the first outcome changes the composition of the sample space. Update the second probability before multiplying.
Mini check Check your understanding A jar contains 4 green and 6 yellow beads. What is the probability of selecting a green bead?
\(rac{2}{5}\) \(rac{3}{5}\) \(rac{2}{3}\) \(rac{4}{6}\) Show answer and explanation Answer: \(rac{2}{5}\)
\(4/(4+6)=4/10=2/5\) .
← SAT strategy and application Key takeaways → Key takeaways What to remember Define the relevant sample space before choosing a denominator. Translate ‘and,’ ‘or,’ ‘given,’ and ‘at least one’ carefully. Update probabilities for selections without replacement. Use complements when the opposite event is simpler to calculate. ← Mistakes and traps Continue learning Put these notes into practice Apply the ideas with SAT-style questions, then reinforce key details with flashcards.