These shapes share familiar appearances, but SAT solutions must come from stated definitions and markings. Start by naming the shape and its guaranteed properties.
Definitions and guaranteed structure
| Shape | Definition | Diagonal facts |
|---|---|---|
| Rectangle | Quadrilateral with four right angles | Congruent and bisect each other |
| Square | Four right angles and four congruent sides | Congruent and bisect each other |
| Trapezoid | Exactly one pair of parallel sides | No general congruence conclusion |
| Isosceles trapezoid | A trapezoid with congruent legs | Diagonals are congruent |
Rectangle diagonals
A diagonal is the hypotenuse of a right triangle whose legs are the rectangle dimensions.
Half a rectangle diagonal
A rectangle is 12 by 16. Its diagonals meet at E. Find the distance from E to a vertex.
- Full diagonal
\(d=\sqrt{12^2+16^2}=20\).
- Bisect
E is the diagonal midpoint, so the requested distance is \(20/2\).
Squares and 45-45-90 diagonals
A square diagonal forms two 45-45-90 triangles.
Area from a square diagonal
A square has diagonal \(14\sqrt2\). Find its area.
- Side
\(s=d/\sqrt2=14\).
- Area
\(A=14^2=196\).
Trapezoid anatomy and midsegment
- Trapezoid
- For this chapter, a quadrilateral with exactly one pair of parallel sides. The parallel sides are bases; the nonparallel sides are legs.
The segment joining the leg midpoints is parallel to both bases and has their average length.
Recover a missing base
A trapezoid has midsegment 17 and one base 12. Find the other base.
- Average
\(17=(12+b_2)/2\).
- Solve
\(34=12+b_2\), so \(b_2=22\).
Isosceles trapezoids
Trapezoid area
The second form follows because the midsegment is the average of the bases. Height is perpendicular distance between base lines.
Height from a right triangle
An isosceles trapezoid has bases 14 and 24 and legs 13. Find its area.
- Horizontal offset
Symmetry splits the base difference: \((24-14)/2=5\).
- Height
The leg, offset, and height form a 5-12-13 triangle, so \(h=12\).
- Area
\(A=\tfrac12(12)(14+24)=228\).
Midsegment and area
Bases are 10 and 18 and height is 7. Find the midsegment and area.
Show answer and explanation
Answer: Midsegment 14; area 98.
Average the bases, then use \(A=mh\).
Key takeaways
- Rectangle diagonals are congruent and bisect each other; their intersection creates four equal-area triangles.
- A square has \(A=s^2\) and diagonal \(s\sqrt2\).
- This source uses exactly one parallel-side pair to define a trapezoid.
- The trapezoid midsegment averages the bases, and area equals midsegment times perpendicular height.
Put these notes into practice
Apply the ideas with SAT-style questions, then reinforce key details with flashcards.