MathChapter 12: Composition, Recursion, and Exponential Functions
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Prompt
What is the source-supported exponential form?
Answer
\(f(x)=ab^x\), with \(a\ne0\), \(b>0\), and \(b\ne1\).
Prompt
In \(f(x)=ab^x\), what is \(f(0)\)?
Answer
\(a\), because \(b^0=1\).
Prompt
What is the vertical-axis intercept of \(ab^x\)?
Answer
\((0,a)\).
Prompt
Which parameter is the one-step multiplier?
Answer
The base \(b\).
Prompt
When does the source classify \(ab^x\) as growth?
Answer
When \(b>1\).
Prompt
When does it classify \(ab^x\) as decay?
Answer
When \(0<b<1\).
Prompt
Does a positive value of \(a\) by itself mean growth?
Answer
No. Growth or decay is determined by the base \(b\).
Prompt
For the positive-scale source cases, what is the domain?
Answer
All real numbers.
Prompt
For the positive-scale source cases, what is the range?
Answer
The positive real numbers.
Prompt
What pattern in a table suggests an exponential model?
Answer
A constant ratio between consecutive outputs for equal input steps.
Prompt
What pattern suggests a linear model instead?
Answer
A constant additive difference.
Prompt
How should an accurate exponential graph be built?
Answer
Equation to exact values to plotted points to curve.
Prompt
Why is hand-sketching a curve before choosing a model risky?
Answer
The sketch may imply values or an intercept that do not satisfy the equation.
Prompt
What is average rate of change on \([u,v]\)?
Answer
\(\frac{f(v)-f(u)}{v-u}\).
Prompt
Is average rate of change the same as the exponential base?
Answer
No. One is an interval-based additive average; the other is a one-step multiplier.
Prompt
What must you check before comparing two curves visually?
Answer
Their axis scales and exact values at common inputs.
Prompt
For \(q(x)=9(1.4)^x\), identify \(a\) and \(b\).
Answer
\(a=9\) and \(b=1.4\).
Prompt
For \(h(x)=32(0.75)^x\), what percent is retained per step?
Answer
\(75\%\); the model decays by \(25\%\).
Prompt
If \(f(0)=6\) and each output is twice the preceding output, what model fits?
Answer
\(f(x)=6(2)^x\).
Prompt
Why can a lower-starting growth model overtake another?
Answer
A larger repeated multiplier can eventually outweigh a smaller initial value.
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