Practice
Percent Word Problems Practice
Fifty original questions covering price changes, tax, mixtures, investments, subgroups, repeated changes, reverse models, and error analysis.
- Answered
- 0 / 50
- Correct
- 0
- Incorrect
- 0
- Accuracy
- 0%
Question 1
Explanation
The remaining-price multiplier is \(0.75\). The sale price is \(\$160(0.75)=\$120.00\).
Question 2
Explanation
The remaining-price multiplier is \(0.65\). The sale price is \(\$240(0.65)=\$156.00\).
Question 3
Explanation
The remaining-price multiplier is \(0.85\). The sale price is \(\$84(0.85)=\$71.40\).
Question 4
Explanation
The remaining-price multiplier is \(0.8200000000000001\). The sale price is \(\$125(0.8200000000000001)=\$102.50\).
Question 5
Explanation
The remaining-price multiplier is \(0.875\). The sale price is \(\$72(0.875)=\$63.00\).
Question 6
Explanation
An added \(8.25\%\) uses multiplier \(1.0825\). Thus the total is \(\$48(1.0825)=\$51.96\).
Question 7
Explanation
An added \(32\%\) uses multiplier \(1.32\). Thus the total is \(\$75(1.32)=\$99.00\).
Question 8
Explanation
An added \(18\%\) uses multiplier \(1.18\). Thus the total is \(\$120(1.18)=\$141.60\).
Question 9
Explanation
An added \(6.5\%\) uses multiplier \(1.065\). Thus the total is \(\$280(1.065)=\$298.20\).
Question 10
Explanation
An added \(12.5\%\) uses multiplier \(1.125\). Thus the total is \(\$96(1.125)=\$108.00\).
Question 11
Explanation
Multiply successive factors: \(\$200(0.8)(1.08)=\$172.80\).
Question 12
Explanation
Multiply successive factors: \(\$150(1.3)(0.9)=\$175.50\).
Question 13
Explanation
Multiply successive factors: \(\$320(0.75)(0.85)=\$204.00\).
Question 14
Explanation
Multiply successive factors: \(\$80(1.125)(1.06)=\$95.40\).
Question 15
Explanation
Multiply successive factors: \(\$500(0.6)(1.075)=\$322.50\).
Question 16
Explanation
The final amount satisfies \(F=0.8B\). Therefore \(B=\$144/0.8=\$180.00\).
Question 17
Explanation
The final amount satisfies \(F=1.08B\). Therefore \(B=\$216/1.08=\$200.00\).
Question 18
Explanation
The final amount satisfies \(F=1.25B\). Therefore \(B=\$187.5/1.25=\$150.00\).
Question 19
Explanation
The final amount satisfies \(F=0.875B\). Therefore \(B=\$105/0.875=\$120.00\).
Question 20
Explanation
The final amount satisfies \(F=1.15B\). Therefore \(B=\$138/1.15=\$120.00\).
Question 21
Explanation
The active amounts are \(2(0.2)\) and \(3(0.5)\). Their sum divided by \(5\) liters is \(0.38\), or \(38\%\).
Question 22
Explanation
The active amounts are \(4(0.15)\) and \(6(0.35)\). Their sum divided by \(10\) liters is \(0.27\), or \(27\%\).
Question 23
Explanation
The active amounts are \(5(0.12)\) and \(3(0.32)\). Their sum divided by \(8\) liters is \(0.195\), or \(19.5\%\).
Question 24
Explanation
The active amounts are \(7(0.4)\) and \(3(0.1)\). Their sum divided by \(10\) liters is \(0.31\), or \(31\%\).
Question 25
Explanation
The active amounts are \(1.5(0.6)\) and \(2.5(0.24)\). Their sum divided by \(4\) liters is \(0.375\), or \(37.5\%\).
Question 26
Explanation
Let \(x\) be invested at \(7\%\). Then \(0.03(10000-x)+0.07x=540\), which solves to \(x=\$6000.00\).
Question 27
Explanation
Let \(x\) be invested at \(5\%\). Then \(0.02(8000-x)+0.05x=310\), which solves to \(x=\$5000.00\).
Question 28
Explanation
Let \(x\) be invested at \(8\%\). Then \(0.04(15000-x)+0.08x=900\), which solves to \(x=\$7500.00\).
Question 29
Explanation
Let \(x\) be invested at \(6.5\%\). Then \(0.025(12000-x)+0.065x=580\), which solves to \(x=\$7000.00\).
Question 30
Explanation
Let \(x\) be invested at \(5.5\%\). Then \(0.035(20000-x)+0.055x=900\), which solves to \(x=\$10000.00\).
Question 31
Explanation
Apply the nested rates in sequence: \(800(0.35)(0.4)=112\).
Question 32
Explanation
Apply the nested rates in sequence: \(1250(0.48)(0.25)=150\).
Question 33
Explanation
Apply the nested rates in sequence: \(960(0.625)(0.3)=180\).
Question 34
Explanation
Apply the nested rates in sequence: \(1500(0.24)(0.45)=162\).
Question 35
Explanation
Apply the nested rates in sequence: \(720(0.75)(0.2)=108\).
Question 36
Explanation
The remaining factors are \(0.7\) and \(0.8\). Thus \(500(0.7)(0.8)=280\).
Question 37
Explanation
The remaining factors are \(0.75\) and \(0.9\). Thus \(840(0.75)(0.9)=567\).
Question 38
Explanation
The remaining factors are \(0.6\) and \(0.85\). Thus \(1200(0.6)(0.85)=612\).
Question 39
Explanation
The remaining factors are \(0.875\) and \(0.75\). Thus \(960(0.875)(0.75)=630\).
Question 40
Explanation
The remaining factors are \(0.8\) and \(0.65\). Thus \(1500(0.8)(0.65)=780\).
Question 41
Explanation
The factors give \(0.80(1.10)=0.88\), so the net discount is \(12\%\).
Question 42
Explanation
Concentrations must be weighted by their solution amounts.
Question 43
Explanation
The two principal portions are complementary and must add to the total.
Question 44
Explanation
The sale price is \(80\%\) of the original, so divide \(72/0.80\).
Question 45
Explanation
The subgroup is the whole for the second percent, so apply the rates sequentially.
Question 46
Explanation
Model each percent against its actual base, then solve the resulting multiplier, conservation, or allocation equation.
Question 47
Explanation
Model each percent against its actual base, then solve the resulting multiplier, conservation, or allocation equation.
Question 48
Explanation
Model each percent against its actual base, then solve the resulting multiplier, conservation, or allocation equation.
Question 49
Explanation
Model each percent against its actual base, then solve the resulting multiplier, conservation, or allocation equation.
Question 50
Explanation
Model each percent against its actual base, then solve the resulting multiplier, conservation, or allocation equation.
Keyboard: use Tab to move, arrow keys to change answer choices, and Enter to check an answer.
Your practice summary
Use the results to decide what to review before your next attempt.
- Correct
- 0
- Incorrect
- 0
- Completed
- 50 / 50
Questions to review
No mistakes this time. Excellent work.
- Question 1Discount applicationsEasy
- Question 2Discount applicationsEasy
- Question 3Discount applicationsEasy
- Question 4Discount applicationsEasy
- Question 5Discount applicationsEasy
- Question 6Tax, markup, and added ratesEasy
- Question 7Tax, markup, and added ratesEasy
- Question 8Tax, markup, and added ratesEasy
- Question 9Tax, markup, and added ratesEasy
- Question 10Tax, markup, and added ratesEasy
- Question 11Successive price changesEasy
- Question 12Successive price changesEasy
- Question 13Successive price changesEasy
- Question 14Successive price changesEasy
- Question 15Successive price changesEasy
- Question 16Reverse price applicationsMedium
- Question 17Reverse price applicationsMedium
- Question 18Reverse price applicationsMedium
- Question 19Reverse price applicationsMedium
- Question 20Reverse price applicationsMedium
- Question 21Mixture concentrationMedium
- Question 22Mixture concentrationMedium
- Question 23Mixture concentrationMedium
- Question 24Mixture concentrationMedium
- Question 25Mixture concentrationMedium
- Question 26Investment allocationMedium
- Question 27Investment allocationMedium
- Question 28Investment allocationMedium
- Question 29Investment allocationMedium
- Question 30Investment allocationMedium
- Question 31Percent of a subgroupMedium
- Question 32Percent of a subgroupMedium
- Question 33Percent of a subgroupMedium
- Question 34Percent of a subgroupMedium
- Question 35Percent of a subgroupMedium
- Question 36Multi-stage percent contextsMedium
- Question 37Multi-stage percent contextsMedium
- Question 38Multi-stage percent contextsMedium
- Question 39Multi-stage percent contextsMedium
- Question 40Multi-stage percent contextsMedium
- Question 41Percent word-problem error analysisHard
- Question 42Percent word-problem error analysisHard
- Question 43Percent word-problem error analysisHard
- Question 44Percent word-problem error analysisHard
- Question 45Percent word-problem error analysisHard
- Question 46Advanced percent modelingHard
- Question 47Advanced percent modelingHard
- Question 48Advanced percent modelingHard
- Question 49Advanced percent modelingHard
- Question 50Advanced percent modelingHard