An inscribed angle has its vertex on the circle. Its sides are chords, and the arc lying between those sides—opposite the vertex—is the intercepted arc.
The inscribed-angle theorem
Equivalently, the intercepted arc is twice the inscribed angle.
Arc from an inscribed angle
An inscribed angle measures \(47^\circ\). Find its intercepted arc.
- Double
\(m\widehat{BC}=2(47^\circ)=94^\circ\).
Three SAT corollaries
| Condition | Conclusion | Fast recognition |
|---|---|---|
| Same intercepted arc | Inscribed angles are congruent | Trace both angle sides to the same endpoints |
| Intercepted arc is a semicircle | Inscribed angle is \(90^\circ\) | One side-to-side chord is a diameter |
| Quadrilateral inscribed in a circle | Opposite angles total \(180^\circ\) | All four vertices lie on the circle |
Figure not drawn to scale.
Cyclic quadrilateral algebra
Opposite angles in a cyclic quadrilateral are \(3x+6\) and \(5x-10\) degrees. Find x.
- Supplement
\((3x+6)+(5x-10)=180\), so \(8x=184\).
Diameter check
Triangle ABC is inscribed in a circle and AC is a diameter. If \(\angle A=34^\circ\), find \(\angle B\) and \(\angle C\).
Show answer and explanation
Answer: \(\angle B=90^\circ\), \(\angle C=56^\circ\).
The angle opposite diameter AC is right; triangle angles then total 180 degrees.
Key takeaways
- An inscribed angle is half its intercepted arc.
- Inscribed angles intercepting the same arc are congruent.
- An angle inscribed in a semicircle is right.
- Opposite angles of a cyclic quadrilateral are supplementary.
Put these notes into practice
Apply the ideas with SAT-style questions, then reinforce key details with flashcards.