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MathChapter 19: Circles
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Chord theorems translate curved information into straight-segment information. They also create right triangles that connect radius, half-chord, and distance from the center.

The chord theorem set

Arc and chord theorems
Given in the same or congruent circlesConclusionConverse?
Congruent arcsTheir chords are congruentYes
Diameter perpendicular to a chordIt bisects the chord and intercepted arcUse only the stated direction here
Chords equidistant from the centerThe chords are congruentYes
Congruent arcs and chordsTwo congruent arcs in the same circle subtend congruent chords.
Congruent arcs and chordsTwo congruent arcs in the same circle subtend congruent chords.ccOABCD
Congruent arcs and chords
Perpendicular diameter bisects a chordA diameter meets a chord perpendicularly, bisecting both the chord and its intercepted arc.
Perpendicular diameter bisects a chordA diameter meets a chord perpendicularly, bisecting both the chord and its intercepted arc.616/210OABCD
Perpendicular diameter bisects a chord
Equidistant chordsTwo chords lie the same perpendicular distance d from the center and therefore are congruent.
Equidistant chordsTwo chords lie the same perpendicular distance d from the center and therefore are congruent.ddOABCD
Equidistant chords

The chord-distance model

Radius, half-chord, and center distanceA perpendicular from the center bisects a chord and forms a right triangle with legs d and c over 2 and hypotenuse r.
Radius, half-chord, and center distanceA perpendicular from the center bisects a chord and forms a right triangle with legs d and c over 2 and hypotenuse r.dc/2rOABCD
Radius, half-chord, and center distance
Radius–distance–chord relationship
\[d^2+\left(\frac c2\right)^2=r^2\]

The perpendicular center-to-chord segment bisects the chord, so the triangle leg is c/2, not c.

Worked example

Distance from center to chord

A circle has radius 13 and a chord of length 10. Find the perpendicular distance from the center to the chord.

  1. Bisect chord

    Half the chord is 5.

  2. Pythagorean equation

    \(d^2+5^2=13^2\), so \(d^2=144\).

\(d=12\).
Worked example

Find a chord

A chord is 8 units from the center of a circle of radius 10. Find the chord length.

  1. Half-chord

    \((c/2)^2+8^2=10^2\), so \(c/2=6\).

  2. Double

    The complete chord is \(c=12\).

12 units.
Mini check

Chord check

A radius is 17 and the center-to-chord distance is 15. Find the chord.

Show answer and explanation

Answer: 16 units.

The half-chord is \(\sqrt{17^2-15^2}=8\), then double.

Key takeaways

Key takeaways

  • Congruent arcs and congruent chords correspond in the same or congruent circles.
  • A perpendicular diameter bisects a chord and its arc.
  • Equal center distances correspond to equal chord lengths.
  • Use \(d^2+(c/2)^2=r^2\) and remember the half-chord.
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Put these notes into practice

Apply the ideas with SAT-style questions, then reinforce key details with flashcards.