Practice
Polynomial Functions and Their Graphs Practice
Fifty original questions on degree, zeros, exact polynomial graphs, intervals, extrema, restricted domains, factors, and parameters.
- Answered
- 0 / 50
- Correct
- 0
- Incorrect
- 0
- Accuracy
- 0%
Question 1
Explanation
The greatest exponent with a nonzero coefficient in \(7x^5-2x^2+9\) is \(5\), so the degree is \(5\).
- Method
Ignore term count and coefficient size; identify the greatest exponent with a nonzero coefficient.
- Verified result
The greatest exponent with a nonzero coefficient in \(7x^5-2x^2+9\) is \(5\), so the degree is \(5\).
Question 2
Explanation
The greatest exponent with a nonzero coefficient in \(-3x^4+x^3-8\) is \(4\), so the degree is \(4\).
- Method
Ignore term count and coefficient size; identify the greatest exponent with a nonzero coefficient.
- Verified result
The greatest exponent with a nonzero coefficient in \(-3x^4+x^3-8\) is \(4\), so the degree is \(4\).
Question 3
Explanation
The greatest exponent with a nonzero coefficient in \(11-6x+x^2\) is \(2\), so the degree is \(2\).
- Method
Ignore term count and coefficient size; identify the greatest exponent with a nonzero coefficient.
- Verified result
The greatest exponent with a nonzero coefficient in \(11-6x+x^2\) is \(2\), so the degree is \(2\).
Question 4
Explanation
The greatest exponent with a nonzero coefficient in \(9x-14\) is \(1\), so the degree is \(1\).
- Method
Ignore term count and coefficient size; identify the greatest exponent with a nonzero coefficient.
- Verified result
The greatest exponent with a nonzero coefficient in \(9x-14\) is \(1\), so the degree is \(1\).
Question 5
Explanation
The greatest exponent with a nonzero coefficient in \(-12\) is \(0\), so the degree is \(0\).
- Method
Ignore term count and coefficient size; identify the greatest exponent with a nonzero coefficient.
- Verified result
The greatest exponent with a nonzero coefficient in \(-12\) is \(0\), so the degree is \(0\).
Question 6
Explanation
A polynomial's number of real zeros cannot exceed its degree, so the maximum possible count is \(1\). This is an upper bound, not a guarantee.
- Method
Use the degree as the maximum possible real-zero count; do not assume every zero is real.
- Verified result
A polynomial's number of real zeros cannot exceed its degree, so the maximum possible count is \(1\). This is an upper bound, not a guarantee.
Question 7
Explanation
A polynomial's number of real zeros cannot exceed its degree, so the maximum possible count is \(2\). This is an upper bound, not a guarantee.
- Method
Use the degree as the maximum possible real-zero count; do not assume every zero is real.
- Verified result
A polynomial's number of real zeros cannot exceed its degree, so the maximum possible count is \(2\). This is an upper bound, not a guarantee.
Question 8
Explanation
A polynomial's number of real zeros cannot exceed its degree, so the maximum possible count is \(3\). This is an upper bound, not a guarantee.
- Method
Use the degree as the maximum possible real-zero count; do not assume every zero is real.
- Verified result
A polynomial's number of real zeros cannot exceed its degree, so the maximum possible count is \(3\). This is an upper bound, not a guarantee.
Question 9
Explanation
A polynomial's number of real zeros cannot exceed its degree, so the maximum possible count is \(4\). This is an upper bound, not a guarantee.
- Method
Use the degree as the maximum possible real-zero count; do not assume every zero is real.
- Verified result
A polynomial's number of real zeros cannot exceed its degree, so the maximum possible count is \(4\). This is an upper bound, not a guarantee.
Question 10
Explanation
A polynomial's number of real zeros cannot exceed its degree, so the maximum possible count is \(6\). This is an upper bound, not a guarantee.
- Method
Use the degree as the maximum possible real-zero count; do not assume every zero is real.
- Verified result
A polynomial's number of real zeros cannot exceed its degree, so the maximum possible count is \(6\). This is an upper bound, not a guarantee.
Question 11
Explanation
Substitute \(x=2\) into every power of the polynomial. Careful evaluation gives \(f(2)=6\).
- Method
Use parentheses around negative inputs and evaluate powers before multiplication and addition.
- Verified result
Substitute \(x=2\) into every power of the polynomial. Careful evaluation gives \(f(2)=6\).
Question 12
Explanation
Substitute \(x=-1\) into every power of the polynomial. Careful evaluation gives \(f(-1)=-6\).
- Method
Use parentheses around negative inputs and evaluate powers before multiplication and addition.
- Verified result
Substitute \(x=-1\) into every power of the polynomial. Careful evaluation gives \(f(-1)=-6\).
Question 13
Explanation
Substitute \(x=-2\) into every power of the polynomial. Careful evaluation gives \(f(-2)=6\).
- Method
Use parentheses around negative inputs and evaluate powers before multiplication and addition.
- Verified result
Substitute \(x=-2\) into every power of the polynomial. Careful evaluation gives \(f(-2)=6\).
Question 14
Explanation
Substitute \(x=3\) into every power of the polynomial. Careful evaluation gives \(f(3)=15\).
- Method
Use parentheses around negative inputs and evaluate powers before multiplication and addition.
- Verified result
Substitute \(x=3\) into every power of the polynomial. Careful evaluation gives \(f(3)=15\).
Question 15
Explanation
Substitute \(x=4\) into every power of the polynomial. Careful evaluation gives \(f(4)=0\).
- Method
Use parentheses around negative inputs and evaluate powers before multiplication and addition.
- Verified result
Substitute \(x=4\) into every power of the polynomial. Careful evaluation gives \(f(4)=0\).
Question 16
Explanation
Zeros are horizontal coordinates where the curve meets the horizontal axis. The generated curve crosses or touches at \(-3,0,2\), and each value makes its factored polynomial equal zero.
- Method
Read horizontal coordinates of axis intersections; do not report vertical coordinates.
- Verified result
Zeros are horizontal coordinates where the curve meets the horizontal axis. The generated curve crosses or touches at \(-3,0,2\), and each value makes its factored polynomial equal zero.
Question 17
Explanation
Zeros are horizontal coordinates where the curve meets the horizontal axis. The generated curve crosses or touches at \(-2,3\), and each value makes its factored polynomial equal zero.
- Method
Read horizontal coordinates of axis intersections; do not report vertical coordinates.
- Verified result
Zeros are horizontal coordinates where the curve meets the horizontal axis. The generated curve crosses or touches at \(-2,3\), and each value makes its factored polynomial equal zero.
Question 18
Explanation
Zeros are horizontal coordinates where the curve meets the horizontal axis. The generated curve crosses or touches at \(-3,-1,1,3\), and each value makes its factored polynomial equal zero.
- Method
Read horizontal coordinates of axis intersections; do not report vertical coordinates.
- Verified result
Zeros are horizontal coordinates where the curve meets the horizontal axis. The generated curve crosses or touches at \(-3,-1,1,3\), and each value makes its factored polynomial equal zero.
Question 19
Explanation
Zeros are horizontal coordinates where the curve meets the horizontal axis. The generated curve crosses or touches at \(-2,1,4\), and each value makes its factored polynomial equal zero.
- Method
Read horizontal coordinates of axis intersections; do not report vertical coordinates.
- Verified result
Zeros are horizontal coordinates where the curve meets the horizontal axis. The generated curve crosses or touches at \(-2,1,4\), and each value makes its factored polynomial equal zero.
Question 20
Explanation
Zeros are horizontal coordinates where the curve meets the horizontal axis. The generated curve crosses or touches at \(-1\), and each value makes its factored polynomial equal zero.
- Method
Read horizontal coordinates of axis intersections; do not report vertical coordinates.
- Verified result
Zeros are horizontal coordinates where the curve meets the horizontal axis. The generated curve crosses or touches at \(-1\), and each value makes its factored polynomial equal zero.
Question 21
Explanation
The displayed equation has greatest power \(3\). Its 3 visible real zeros do not change that algebraic degree.
- Method
Use the equation's greatest exponent; graph crossings alone may not reveal every degree detail.
- Verified result
The displayed equation has greatest power \(3\). Its 3 visible real zeros do not change that algebraic degree.
Question 22
Explanation
The displayed equation has greatest power \(2\). Its 2 visible real zeros do not change that algebraic degree.
- Method
Use the equation's greatest exponent; graph crossings alone may not reveal every degree detail.
- Verified result
The displayed equation has greatest power \(2\). Its 2 visible real zeros do not change that algebraic degree.
Question 23
Explanation
The displayed equation has greatest power \(4\). Its 4 visible real zeros do not change that algebraic degree.
- Method
Use the equation's greatest exponent; graph crossings alone may not reveal every degree detail.
- Verified result
The displayed equation has greatest power \(4\). Its 4 visible real zeros do not change that algebraic degree.
Question 24
Explanation
The displayed equation has greatest power \(3\). Its 3 visible real zeros do not change that algebraic degree.
- Method
Use the equation's greatest exponent; graph crossings alone may not reveal every degree detail.
- Verified result
The displayed equation has greatest power \(3\). Its 3 visible real zeros do not change that algebraic degree.
Question 25
Explanation
The displayed equation has greatest power \(1\). Its 1 visible real zero do not change that algebraic degree.
- Method
Use the equation's greatest exponent; graph crossings alone may not reveal every degree detail.
- Verified result
The displayed equation has greatest power \(1\). Its 1 visible real zero do not change that algebraic degree.
Question 26
Explanation
The graph has an intercept at horizontal coordinate \(-3\), so \(f(-3)=0\). The corresponding factor is \(x-(-3)=x+3\).
- Method
Translate a zero c into the factor x-c, keeping the sign reversal visible.
- Verified result
The graph has an intercept at horizontal coordinate \(-3\), so \(f(-3)=0\). The corresponding factor is \(x-(-3)=x+3\).
Question 27
Explanation
The graph has an intercept at horizontal coordinate \(-2\), so \(f(-2)=0\). The corresponding factor is \(x-(-2)=x+2\).
- Method
Translate a zero c into the factor x-c, keeping the sign reversal visible.
- Verified result
The graph has an intercept at horizontal coordinate \(-2\), so \(f(-2)=0\). The corresponding factor is \(x-(-2)=x+2\).
Question 28
Explanation
The graph has an intercept at horizontal coordinate \(-3\), so \(f(-3)=0\). The corresponding factor is \(x-(-3)=x+3\).
- Method
Translate a zero c into the factor x-c, keeping the sign reversal visible.
- Verified result
The graph has an intercept at horizontal coordinate \(-3\), so \(f(-3)=0\). The corresponding factor is \(x-(-3)=x+3\).
Question 29
Explanation
The graph has an intercept at horizontal coordinate \(-2\), so \(f(-2)=0\). The corresponding factor is \(x-(-2)=x+2\).
- Method
Translate a zero c into the factor x-c, keeping the sign reversal visible.
- Verified result
The graph has an intercept at horizontal coordinate \(-2\), so \(f(-2)=0\). The corresponding factor is \(x-(-2)=x+2\).
Question 30
Explanation
The graph has an intercept at horizontal coordinate \(-1\), so \(f(-1)=0\). The corresponding factor is \(x-(-1)=x+1\).
- Method
Translate a zero c into the factor x-c, keeping the sign reversal visible.
- Verified result
The graph has an intercept at horizontal coordinate \(-1\), so \(f(-1)=0\). The corresponding factor is \(x-(-1)=x+1\).
Question 31
Explanation
The curve changes from increasing to decreasing at the labeled point (-1,2), so the requested input is -1.
- Method
Read the curve from left to right and distinguish a point's horizontal input from its vertical function value.
- Verified result
The curve changes from increasing to decreasing at the labeled point (-1,2), so the requested input is -1.
Question 32
Explanation
The local maximum point is (-1,2); the maximum value is its vertical coordinate 2.
- Method
Read the curve from left to right and distinguish a point's horizontal input from its vertical function value.
- Verified result
The local maximum point is (-1,2); the maximum value is its vertical coordinate 2.
Question 33
Explanation
The curve changes from decreasing to increasing at the labeled point (1,-2), so the requested input is 1.
- Method
Read the curve from left to right and distinguish a point's horizontal input from its vertical function value.
- Verified result
The curve changes from decreasing to increasing at the labeled point (1,-2), so the requested input is 1.
Question 34
Explanation
From left to right, the curve falls between its local maximum at x=-1 and local minimum at x=1.
- Method
Read the curve from left to right and distinguish a point's horizontal input from its vertical function value.
- Verified result
From left to right, the curve falls between its local maximum at x=-1 and local minimum at x=1.
Question 35
Explanation
The curve rises before x=-1, falls until x=1, and rises again after x=1.
- Method
Read the curve from left to right and distinguish a point's horizontal input from its vertical function value.
- Verified result
The curve rises before x=-1, falls until x=1, and rises again after x=1.
Question 36
Explanation
Within the stated closed interval, compare the endpoints and the parabola's turning point. The requested minimum value is \(-4\), reached at \(x=0\).
- Method
Ignore points outside the stated interval and report the vertical value when the question asks for a value.
- Verified result
Within the stated closed interval, compare the endpoints and the parabola's turning point. The requested minimum value is \(-4\), reached at \(x=0\).
Question 37
Explanation
Within the stated closed interval, compare the endpoints and the parabola's turning point. The requested maximum value is \(5\), reached at \(x=2\).
- Method
Ignore points outside the stated interval and report the vertical value when the question asks for a value.
- Verified result
Within the stated closed interval, compare the endpoints and the parabola's turning point. The requested maximum value is \(5\), reached at \(x=2\).
Question 38
Explanation
Within the stated closed interval, compare the endpoints and the parabola's turning point. The requested minimum value is \(-4\), reached at \(x=1\).
- Method
Ignore points outside the stated interval and report the vertical value when the question asks for a value.
- Verified result
Within the stated closed interval, compare the endpoints and the parabola's turning point. The requested minimum value is \(-4\), reached at \(x=1\).
Question 39
Explanation
Within the stated closed interval, compare the endpoints and the parabola's turning point. The requested minimum value is \(-4\), reached at \(x=-2\).
- Method
Ignore points outside the stated interval and report the vertical value when the question asks for a value.
- Verified result
Within the stated closed interval, compare the endpoints and the parabola's turning point. The requested minimum value is \(-4\), reached at \(x=-2\).
Question 40
Explanation
Within the stated closed interval, compare the endpoints and the parabola's turning point. The requested minimum value is \(-4\), reached at \(x=2\).
- Method
Ignore points outside the stated interval and report the vertical value when the question asks for a value.
- Verified result
Within the stated closed interval, compare the endpoints and the parabola's turning point. The requested minimum value is \(-4\), reached at \(x=2\).
Question 41
Explanation
Each zero \(c\) contributes factor \(x-c\). Applying that rule to \(-4,2\) gives \((x+4)(x-2)\).
- Method
Translate every listed zero independently into x-c and multiply the factors without changing their signs.
- Verified result
Each zero \(c\) contributes factor \(x-c\). Applying that rule to \(-4,2\) gives \((x+4)(x-2)\).
Question 42
Explanation
Each zero \(c\) contributes factor \(x-c\). Applying that rule to \(-3,1,5\) gives \((x+3)(x-1)(x-5)\).
- Method
Translate every listed zero independently into x-c and multiply the factors without changing their signs.
- Verified result
Each zero \(c\) contributes factor \(x-c\). Applying that rule to \(-3,1,5\) gives \((x+3)(x-1)(x-5)\).
Question 43
Explanation
Each zero \(c\) contributes factor \(x-c\). Applying that rule to \(-2,0,3\) gives \((x+2)x(x-3)\).
- Method
Translate every listed zero independently into x-c and multiply the factors without changing their signs.
- Verified result
Each zero \(c\) contributes factor \(x-c\). Applying that rule to \(-2,0,3\) gives \((x+2)x(x-3)\).
Question 44
Explanation
Each zero \(c\) contributes factor \(x-c\). Applying that rule to \(-1,2,4,6\) gives \((x+1)(x-2)(x-4)(x-6)\).
- Method
Translate every listed zero independently into x-c and multiply the factors without changing their signs.
- Verified result
Each zero \(c\) contributes factor \(x-c\). Applying that rule to \(-1,2,4,6\) gives \((x+1)(x-2)(x-4)(x-6)\).
Question 45
Explanation
Each zero \(c\) contributes factor \(x-c\). Applying that rule to \(0,3\) gives \(x(x-3)\).
- Method
Translate every listed zero independently into x-c and multiply the factors without changing their signs.
- Verified result
Each zero \(c\) contributes factor \(x-c\). Applying that rule to \(0,3\) gives \(x(x-3)\).
Question 46
Explanation
An intercept at \(x=2\) means \(p(2)=0\). The nonparameter terms evaluate to \(-2\), so \(-2+k=0\), giving \(k=2\).
- Method
Turn the x-intercept into a zero function value before solving the parameter equation.
- Verified result
An intercept at \(x=2\) means \(p(2)=0\). The nonparameter terms evaluate to \(-2\), so \(-2+k=0\), giving \(k=2\).
Question 47
Explanation
An intercept at \(x=-1\) means \(p(-1)=0\). The nonparameter terms evaluate to \(-3\), so \(-3+k=0\), giving \(k=3\).
- Method
Turn the x-intercept into a zero function value before solving the parameter equation.
- Verified result
An intercept at \(x=-1\) means \(p(-1)=0\). The nonparameter terms evaluate to \(-3\), so \(-3+k=0\), giving \(k=3\).
Question 48
Explanation
An intercept at \(x=3\) means \(p(3)=0\). The nonparameter terms evaluate to \(5\), so \(5+2k=0\), giving \(k=-2.5\).
- Method
Turn the x-intercept into a zero function value before solving the parameter equation.
- Verified result
An intercept at \(x=3\) means \(p(3)=0\). The nonparameter terms evaluate to \(5\), so \(5+2k=0\), giving \(k=-2.5\).
Question 49
Explanation
An intercept at \(x=-2\) means \(p(-2)=0\). The nonparameter terms evaluate to \(-5\), so \(-5-k=0\), giving \(k=-5\).
- Method
Turn the x-intercept into a zero function value before solving the parameter equation.
- Verified result
An intercept at \(x=-2\) means \(p(-2)=0\). The nonparameter terms evaluate to \(-5\), so \(-5-k=0\), giving \(k=-5\).
Question 50
Explanation
An intercept at \(x=4\) means \(p(4)=0\). The nonparameter terms evaluate to \(-2\), so \(-2+k=0\), giving \(k=2\).
- Method
Turn the x-intercept into a zero function value before solving the parameter equation.
- Verified result
An intercept at \(x=4\) means \(p(4)=0\). The nonparameter terms evaluate to \(-2\), so \(-2+k=0\), giving \(k=2\).
Keyboard: use Tab to move, arrow keys to change answer choices, and Enter to check an answer.
Your practice summary
Use the results to decide what to review before your next attempt.
- Correct
- 0
- Incorrect
- 0
- Completed
- 50 / 50
Questions to review
No mistakes this time. Excellent work.
- Question 1Polynomial degreeEasy
- Question 2Polynomial degreeEasy
- Question 3Polynomial degreeEasy
- Question 4Polynomial degreeEasy
- Question 5Polynomial degreeEasy
- Question 6Maximum possible real zerosEasy
- Question 7Maximum possible real zerosEasy
- Question 8Maximum possible real zerosEasy
- Question 9Maximum possible real zerosEasy
- Question 10Maximum possible real zerosEasy
- Question 11Polynomial evaluationEasy
- Question 12Polynomial evaluationEasy
- Question 13Polynomial evaluationEasy
- Question 14Polynomial evaluationEasy
- Question 15Polynomial evaluationEasy
- Question 16Graph zeros and interceptsMedium
- Question 17Graph zeros and interceptsMedium
- Question 18Graph zeros and interceptsMedium
- Question 19Graph zeros and interceptsMedium
- Question 20Graph zeros and interceptsMedium
- Question 21Graph and polynomial classificationMedium
- Question 22Graph and polynomial classificationMedium
- Question 23Graph and polynomial classificationMedium
- Question 24Graph and polynomial classificationMedium
- Question 25Graph and polynomial classificationMedium
- Question 26Function factors from graph rootsMedium
- Question 27Function factors from graph rootsMedium
- Question 28Function factors from graph rootsMedium
- Question 29Function factors from graph rootsMedium
- Question 30Function factors from graph rootsMedium
- Question 31Increasing decreasing and local extremaMedium
- Question 32Increasing decreasing and local extremaMedium
- Question 33Increasing decreasing and local extremaMedium
- Question 34Increasing decreasing and local extremaMedium
- Question 35Increasing decreasing and local extremaMedium
- Question 36Restricted-domain extremaMedium
- Question 37Restricted-domain extremaMedium
- Question 38Restricted-domain extremaMedium
- Question 39Restricted-domain extremaMedium
- Question 40Restricted-domain extremaMedium
- Question 41Polynomial from rootsHard
- Question 42Polynomial from rootsHard
- Question 43Polynomial from rootsHard
- Question 44Polynomial from rootsHard
- Question 45Polynomial from rootsHard
- Question 46Parameter from polynomial interceptHard
- Question 47Parameter from polynomial interceptHard
- Question 48Parameter from polynomial interceptHard
- Question 49Parameter from polynomial interceptHard
- Question 50Parameter from polynomial interceptHard