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Systems of Equations Practice
Original questions finding and interpreting intersections in nonlinear systems.
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Question 1 of 2
Question 1
Medium
Correct answerExactly two real solutions
Explanation
Set the expressions equal: \(x^2=2x+3\), or \((x-3)(x+1)=0\). Two distinct x-values produce two intersection points.
Question 2 of 2
Question 2
Hard
Correct answer\(20\)
Explanation
Substitution gives \(x^2-5x+4=0=(x-1)(x-4)\). The condition \(x>2\) selects \(x=4\), giving \(y=16\) and \(x+y=20\).
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Questions to review
No mistakes this time. Excellent work.
- Question 1Determine the number of intersectionsMedium
- Question 2Solve a nonlinear systemHard